131(t)=16t^2+96t+3

Solution for 131(t)=16t^2+96t+3 equation:

131(t)=16t^2+96t+3

We move all terms to the left:

131(t)-(16t^2+96t+3)=0

We get rid of parentheses

-16t^2+131t-96t-3=0

We add all the numbers together, and all the variables

-16t^2+35t-3=0

a = -16; b = 35; c = -3;
Δ = b2-4ac
Δ = 352-4·(-16)·(-3)
Δ = 1033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1033}}{2*-16}=\frac{-35-\sqrt{1033}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1033}}{2*-16}=\frac{-35+\sqrt{1033}}{-32}
$